/* sums 1/i from i = 1 to N, both counting "up"
and counting "down."
*/

#include <iostream>
#include <ios>
#include <iomanip>
#include <cmath>
     
using namespace::std;
     
int main ()
     {
  

       int N=0;
       double sumup = 0.;
       double sumdown = 0.;

       cout << " enter integer N: ";
       cin >> N;


       //sum up
       for (int i = 1; i< N+1; ++i){
	 sumup = sumup + 1./(double)i;
       }
       cout << "sumup = " << setprecision(18)<< sumup << setprecision(3)<< endl;
 
//sum down

       for (int i = N; i>0; --i){
	 sumdown = sumdown + 1./(double)i;
 }
       cout << "sumdown = " << setprecision(18) << sumdown << endl;

       return 0;
}