Physics 1304/1404 - Spring 1999

Homework Assignment #3

Due: Thursday 25 February 1999

READING

Chapters 27 and 28.

QUESTIONS

Chapter 27 - 3, 4, 15, 17, 20.
Chapter 28 - 4, 5, 6, 8, 9, 11, 13, 16, 17, 22, 28.

PROBLEMS

Chapter 27 - 4, 16, 19A, 19, 25, 42, 45.
Chapter 28 - 1, 5, 12, 14, 18, 25, 42, 43, 44, 50.

ANSWERS

These are the ANSWERS only, not the SOLUTIONS. It is not sufficient to copy these and turn them in as homework. You must show your work.

Q 27-3) Resistance (R) is the constant of proportionality in most conductors between voltage and current (V=IR); the MKS unit is the ohm. Resistance increases with the length of a conductor and decreases with the cross-sectional area.

Resistivity (rho) is an intrinsic property of the material from which the conductor is made, without regard to its length (L) or cross-sectional area (A). The relation is (R = rho L/A); the MKS unit is the ohm.meter.

Q 27-4) AreaA/AreaB = 1/3; rA/rB = 1/sqrt(3)
Q 27-15) When one electron enters a wire, another electron is pushed out the other end of the wire. The push travels at nearly the speed of light.
Q 27-17) (P = V2/R) The smaller resistance will dissipate more power.
Q 27-20) (R = V2/P) The 25 W bulb has the higher resistance.
(I=V/R) The 100 W bulb carries the greater current.
25 W bulb: R = 484 ohms; I = 0.227 amps.
100 W bulb: R = 121 ohms; I = 0.909 amps.
Q 28-4) Set A is wired with the bulbs (resistors) in parallel; set B is wired in series.
Q 28-5) Connect the resistors in series.
Q 28-6) Connect the resistors in parallel.
Q 28-8) Current only.
Q 28-9) Potential difference (voltage) only.
Q 28-11) Parallel, because one sees cars with only one headlight on.
Q 28-13) Conservation of Charge (junction rule), and Conservation of Energy (loop rule).
Q 28-16) The light glows brightly at first (as bright as it would glow if it were connected across the battery without the capacitor), then grows dimmer exponentially as the cap charges because the current is decreasing exponentially.
Q 28-17) The internal resistance of an ideal ammeter is zero, and the internal resistance of an ideal voltmeter is infinite. Real device only approximate these values.
Q 28-22) No.
Q 28-28)
  1. Lamps A and B glow brighter.
  2. Lamp C is now unlit because it has been shorted out of the circuit.
  3. The current increases.
  4. The voltage drops across both A and B increase; the voltage drop across C is now zero.
  5. The power dissipated increases. Even though only two bulbs are now lit, they use up more power than the three dimmer original bulbs. (Was P=V2/(3R), now is P=V2/(2R))
P 27-4)
  1. 17 A
  2. 85,000 A/m2
P 27-16) 0.310 ohms
P 27-19A) R/9
P 27-19) 1.33 ohms
P 27-25) 6.43 A
P 27-42)
  1. unaffected
  2. doubles
  3. doubles
  4. unaffected
P 27-45) 36.1%
P 28-1)
  1. 7.67 ohms
  2. 1.76 W
P 28-5) 12 ohms
P 28-12) There are many ways to do this.
P 28-14)
  1. 17.1 ohms
  2. current in 4 ohm resistor: 1.99 A
    current in 7 ohm resistor: 1.17 A
    current in 10 ohm resistor: 0.82 A
    current in 9 ohm resistor: 1.99 A
P 28-18)
  1. The 11 ohm resistor uses more power.
  2. (proof required)
  3. The 22 ohm resistor uses more power.
  4. (proof required)
  5. The parallel configuration uses more power.
    parallel: 148.5 W; series: 33 W
P 28-25)
  1. Vb - Va = -10.42 V
  2. I1 = 0.141 A
    I2 = 0.915 A
    I3 = 0.774 A
P 28-42)
  1. 5 s
  2. 150 microcoulombs
  3. 4.06 microamps
P 28-43)
  1. 1.5 s
  2. 1 s
  3. [200 + 100 exp(-t/1s)] microamps
P 28-44)
  1. RC ln(2) = 0.693 RC
  2. an infinite amount of time
P 28-50) 0.982 s

Please report any corrections to Professor Scalise.

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