# Homework Assignment #2

Due:
6 February (Sections 002 and 802)
7 February (Sections 001 and 801)

Chapters 2 and 4.

### QUESTIONS

Chapter 2 - 1, 2, 4, 5, 6, 8, 10, 13.
Chapter 4 - 10, 12, 14, 15, 16, 18.

### PROBLEMS

Chapter 2 - 2, 3, 6, 19, 21, 30, 50, 58.
Chapter 4 - 3, 13, 28, 39, 47.

Q 2-1) They are equal for the case of CONSTANT velocity.
Q 2-2) No, the instantaneous velocity can be zero during the interval.
Q 2-4) Yes.
Q 2-5) Yes.
Q 2-6) Yes.
Q 2-8) They are the same.
Q 2-10) The displacement vector is zero as well.
Q 2-13) 9.8 m/s each second.
Q 4-10) Yes, the point directly under the release point.
Q 4-12) No.
Q 4-14) a) No. b) No. In each case, the magnitude is constant, but the direction of the vector changes.
Q 4-15) Yes, 9.8 m/s2 vertical, 0 m/s2 horizontal
Q 4-16) 60o
Q 4-17) Moon, moon.
Q 4-18) b) acceleration, c) horizontal component of velocity
P 2-2)
1. 180 km North
2. 63 km/h North

P 2-3)
1. 5 m/s
2. 1.25 m/s
3. -2.5 m/s
4. -3.3 m/s
5. 0 m/s

P 2-6)
1. 50 m/s
2. 41 m/s

P 2-19)
1. 20.0 m/s, 5.00 m/s
2. 262 m

P 2-21) [The function should be x(t) = 2.0 + 3.0 t - 1.0 t2]
1. 2 m
2. -3 m/s
3. -2 m/s2

P 2-30)
1. -2.25 x 10-2 m/s2
2. 133 s
3. 1.5 m/s

P 2-50)
1. 98 m/s upward
2. 490 m

P 2-58) 14.0 m
P 4-3)
1. 4.87 km at 209o from East
2. 23.3 m/s
3. 13.5 m/s at 209o from East

P 4-13)
1. 2.67 s
2. 29.9 m/s horizontal
3. (29.9 m/s, -26.2 m/s)

P 4-28)
1. 6 rev/s gives the larger linear speed
2. 1.52 x 103 m/s2
3. 1.28 x 103 m/s2

P 4-39)
1. 30.8 m/s2 downward
2. 70.4 m/s2 upward

P 4-47) 153 km/h at 11.3o North of West

Please report any corrections to Professor Scalise.